Now, answer the following:
a.) What is the probability that the second one selected is defective given that the first one was defective? Round your answer to five decimal places (e.g. 0.65432)
b.) What is the probability that both are defective? Round your answer to seven decimal places (e.g. 8765432)
Three containers are selected, at random, without replacement from the batch.
d.) What is the probability that the third one selected is defective given that the first one selected was defective and the second one selected was okay? Round your answer to five decimal places (e.g. 0.98765)
\frac{6-2}{496-2}=\frac{4}{494}=0.008
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